A system uses 27-bit addresses and it has a 32KB of direct-mapped cache with 8 bytes...

Question

Question

A system uses 27-bit addresses and it has a 32KB of direct-mapped cache with 8 bytes per block. Memory of this system is byte

Answer 1

Answer #1

Solution:

Given,

=> 27-bit addresses

=>Size of cache memory = 32 KB

=>Block size = 8 bytes

Explanation:

=>Number of blocks/lines in the cache = cache size/block size

=>Number of blocks/lines in the cache = 32 KB/8 B

=>Number of blocks/lines in the cache = 32*1024 B/8 B as 1 KB = 1024 B

=>Number of blocks/lines in the cache = 4*1024

=>Number of blocks/lines in the cache = 4096 lines/blocks

I have explained each and every part with the help of statements attached to it.

Answer 2

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