Consider a storage system where main memory is addressed per byte, which uses the direct mapping...
Consider a storage system where main memory is addressed per
byte, which uses the direct mapping method in its cache and where
the format of addresses interpreted by the control system is
Label: 8bits; Line: 12bits; Byte: 4bits;
a) What is the capacity, in bytes, of MP storage?
b) How many lines does the cache have?
c) What storage capacity of the lines?
d) What is the number of main memory blocks assigned to a memory
cache line?
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Consider a storage system where main memory is addressed per
byte, which uses the direct mapping...
Suppose a computer using direct mapped cache has 232 byte of byte-addressable main memory, and a...
Suppose a computer using direct mapped cache has 232 byte of byte-addressable main memory, and a cache of 1024 blocks, where each cache block contains 32 bytes. a. How many blocks of main memory are there? b. What is the format of a memory address as seen by the cache, i.e., what are the sizes of the tag, block, and offset fields? c.To which cache block will the memory address 0x000063FA map?
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A system uses 27-bit addresses and it has a 32KB of direct-mapped cache with 8 bytes per block. Memory of this system is byte-addressed. How many blocks (lines) are in this cache? (don't write your answer in power of two) A/
QUESTION 2 Suppose a computer using direct mapped cache has 216 bytes of byte-addressable main memory...
QUESTION 2 Suppose a computer using direct mapped cache has 216 bytes of byte-addressable main memory and a cache of 64 blocks, where each cache block contains 32 bytes. a. How many blocks of main memory are there? b) What is the format of a memory address as seen by the cache, (include field names and their sizes) c) To which cache block will the memory address (F8C916 map? What address in that block does it map to?
please answer $5 UXIF map in the computer uses direct mapping Question 18 5 pts Suppose...
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$5 UXIF map in the computer uses direct mapping Question 18 5 pts Suppose we have a byte-addressable computer using 2-way set associative mapping with 16-bit main memory addresses and 32 blocks of cache. Suppose also that each block contains 8 bytes. The size of the block offset field is bits, the bits. size of the set field is bits, and the size of the tag field is 5 pts Question 19 Suppose we have a byte-addressable computer...
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Assume the cache can hold 64 kB. Data are transferred between main memory and the cache in blocks of 4 bytes each. This means that the cache is organized as 16K=2^14 lines of 4 bytes each. The main memory consists of 16 MB, with each byte directly addressable by a 24-bit address (2^24 =16M). Thus, for mapping purposes, we can consider main memory to consist of 4M blocks of 4 bytes each. Please show illustrations too for all work. Part...
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Example 4.2 For all three cases, the example includes the following elements: The cache can hold 64 Kbytes. Data are transferred between main memory and the cache in blocks of 4 bytes each. This means that the cache is organized as 16K = 214 lines of 4 bytes each. The main memory consists of 16 Mbytes, with each byte directly addressable by a 24-bit address (24 = 16M). Thus, for mapping purposes, we can consider main memory to consist of...
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Given: An 8-bit computer system with 4 MB of main memory. It has a 16K-words direct-mapped cache with a block size of 16 Bytes. Sought: Calculate the cache line number when Byte address2271len from main memory is mapped to cache. Consider that numbering of main memory blocks and cache lines starts from zero. Express your answer in hexadecimal. It is required to show ALL incremental steps of the solution.
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Question 28 7 pts Consider a byte-addressable computer with 24-bit addresses, a cache capable of storing a total of 64K bytes of data, and blocks of 32 bytes. If the computer uses direct mapping, the format of the memory address is as follows: bits for the tag field, bits for the cache block number, and bits for the block offset.
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please answer
$5 UXIF map in the computer uses direct mapping Question 18 5 pts Suppose we have a byte-addressable computer using 2-way set associative mapping with 16-bit main memory addresses and 32 blocks of cache. Suppose also that each block contains 8 bytes. The size of the block offset field is bits, the bits. size of the set field is bits, and the size of the tag field is 5 pts Question 19 Suppose we have a byte-addressable computer...
Example 4.2 For all three cases, the example includes the following elements: The cache can hold 64 Kbytes. Data are transferred between main memory and the cache in blocks of 4 bytes each. This means that the cache is organized as 16K = 214 lines of 4 bytes each. The main memory consists of 16 Mbytes, with each byte directly addressable by a 24-bit address (24 = 16M). Thus, for mapping purposes, we can consider main memory to consist of...
Given: An 8-bit computer system with 4 MB of main memory. It has a 16K-words direct-mapped cache with a block size of 16 Bytes. Sought: Calculate the cache line number when Byte address2271len from main memory is mapped to cache. Consider that numbering of main memory blocks and cache lines starts from zero. Express your answer in hexadecimal. It is required to show ALL incremental steps of the solution.
Question 28 7 pts Consider a byte-addressable computer with 24-bit addresses, a cache capable of storing a total of 64K bytes of data, and blocks of 32 bytes. If the computer uses direct mapping, the format of the memory address is as follows: bits for the tag field, bits for the cache block number, and bits for the block offset.
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