HA <------> H+ + A-
Ka = [H+][A-]/[HA]
If concentrations of HA and A- are same then the equation of Ka becomes as written below.
Ka = [H+]
pH = -log(Ka)
= -log(7*10^-3)
= 2.15
= 2.2
An acid, HA, has an acid dissociation constant of 7*10-3. Which of the following is the...
If a weak acid has a dissociation constant of 2.2×10^−8, what is the dissociation constant of its conjugate base?
(a) A 0.002 M solution of HA has a pH of 3, calculate the % dissociation of the acid. (b) A 4e-4 of HA solution dissociated by 20 %. Calculate the pH of the solution. (c) A 0.03 M solution of A^- (conjugate base a HA) and 0.03 M of strong acid are combined and results with a pH of 7. What is the pH of a 0.004 M solution of HA? (d) What starting concentration of HA would be...
The following equation represents the dissociation of propionic acid in water. HC3H502(aq) + H20(1) = H30+(aq) + C3H502 (aq) The value for the acid-dissociation constant for propionic acid (HC3H502) is 1.3x10-5 at 25°C. Calculate the hydronium ion concentration present in a propionic acid solution that has the following equilibrium concentrations. 3.24x10-2 mol/L HC3H502 3.06x10-4 mol/L for propionic acid's conjugate base, C3H5027 The general form of the acid-dissociation constant is Ka = [H30'A ], where Ka is the acid-dissociation constant, [HA]...
An acid HA has a Ka of 10-7. The pH of a 0.1 M solution of its conjugate base is: options: 7 5 10 13
A diprotic acid, H,A, has acid dissociation constants of Ka molar concentrations of H,A, HA-, and A2- at equilibrium for each of the solutions 1.42 x 10-4 and Ka2 = 4.07 x 1012. Calculate the pH and = A 0.210 M solution of H,A H2A] = pH HA- A2- М М A 0.210 M solution of NaHA HA pH= М
A weak acid, (HA), has an acid dissociation constant of 4.60∙10–6. A 25.00 ml sample with a concentration of 0.1200 M is titrated with 0.1500 M NaOH. a. Write the equation for the acid dissociation equilibrium. b. What is the pH of the original 0.1200 M sample of HA? c. What is the percent ionization of the 0.1200 M acid? d. Write the equation for the neutralization reaction. e. What is the pH after 8.00 ml NaOH have been added?
A diprotic acid, H2A, has acid dissociation constants of
Ka1=1.01×10−4 and Ka2=4.08×10−12. Calculate the pH and molar
concentrations of H2A, HA−, and A2−at equilibrium for each of the
solutions.
A diprotic acid, H, A, has acid dissociation constants of Kal = 1.01 x 104 and K22 = 4.08 x 10-12. Calculate the pH and molar concentrations of H, A, HA, and A? at equilibrium for each of the solutions. A 0.176 M solution of H, A. pH= pH = 1...
14. A weak acid, (HA), has an acid dissociation constant of 2.50 . 10-6. A 25.00 ml sample with a concentration of 0.250 M is titrated with 0.150 M NaOH. a. Write the equation for the acid dissociation equilibrium. b. What is the pH of the original 0.250 M sample of HA? c. What is the percent ionization of the 0.250 M acid? d. Write the equation for the neutralization reaction. e. What is the pH after 12.00 ml 0.150M...
HA(aq) is a weak acid with a dissociation constant, Ka, of 1.0 x 10-11. What is the pH of a solution 0.055 M in A-(aq)? The temperature is 25oC.
Given its acid dissociation constant (Ka) which of the following is the weakest acid? A-HClO2 (1.1 × 10−2) B-HCOOH (1.8 × 10−4) C- HCN (4.9 × 10−10) D-HF (3.5 × 10−4)