Question

part c and d only

Limiting Reactants Review Constants Periodic Table The octane rating of gasoline is a relationship of the burning ency of the given gasoline mure to the burning efficiency of octane Cloure Timothydrocarbons, octane reacts with owongas to produce carbon dioxide and water. The unbalanced equation for this reactions CH() +0,(9)00,($) + H0 (9) Determine the balanced chemical for reaction C...() +0,(9)-100, (a) + H2O() Enter the coeficients for each compound in order separated by commes. For example,1,1,3, would indicate the mole of C.H... two moles of Oy, three moles of C0, and four moles of 1,0 View Available 2.25,16,18 ✓ Correct It is important to balance a chemical gation before using it for calculations. Checking the equations are balanced will help you avoid many errors in chemistry probleme Balanced chemical equation 2CH() +250,(0)-1600,($)+18,0) Figure 101 Part 0.320 mol of octane is lowed to react 071 mol of eye. Which is the inting reactant? View Available) Previous ✓ Correct Now that you have identified oxygen as the long reactant, you can use the number of moes of oxygen to find the numbers of moles of the other substances

Answer 1

Balanced chemical equation;

2C8H18(g) + 25O2(g) >>>>> 16CO2(g) + 18H2O(g)

Part C ; amount of product to be formed depends upon the amount of limiting reagent available.

As 0.710mol of oxygen is the limiting reagent and this will produce water as;

(18mol-water/25mol-O2)×0.710mol-O2 = 0.511mol of water will produce.

Part D ; moles of octane will get used by 0.710mol of oxygen   ;  

(2mol-octane/25mol-O2)× 0.710mol-O2 = 0.0568mol of octane .

Moles of octane will left after reaction = initial moles of octane - used by oxygen during reaction = 0.320mol - 0.0568mol = 0.263mol of octane will left .