Question

Consider the hypothesis statement shown below using a 0.05 and the data to the right from two independent samples. Х,-113 x2-129 ơ,-41 ơ,-33 40 2-55 a) Calculate the appropriate test statistic and interpret the result. b) Calculate the p-value and interpret the result. Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table a) The test statistic is Round to two decimal places as needed.) Determine the appropriate critical value(s). The critical value(s) is(are) L Round to three decimal places as needed. Use a comma to separate answers as needed.) Since the test statistic Ho. There is ▼| in the rejection region, evidence to conclude that the mean of population 1 is less than the mean of population 2. b) The p-value is Round to three decimal places as needed.) Ho. There is Since the p-value is evidence to conclude that the mean of population 1 is less than the mean of population 2

Answer 1

Date: 13/05/2019 Answer s that the population mean i is less than the population mean 2 at 5% significance level. The null and alternative hypothesis is, < 0 a) The z-test statistics is, n2 (113 -129)-0 412 332 40 55 =-2.03

The z-test statistics is |-2.03 The z-critical value is, From the standard normal table, the z-critical value for left-tailed at 95% confidence is- 1.645. The z-critical value is -1.645 Decision The z value corresponds to sample statistics 1s talls in the critical region, so the null hypothesis is rejected at 5% level of significance. There is sufficient evidence to indicate that the population mean 1 is less than the population mean 2. The result is statistically significant b) Thep-value is,

From the standard normal distribution table, the associated probability for the area to the left is shown below. p(z <-2.03) 0.021 Thep-value is 0.021 Decision The conclusion is that the p-value in this context is less than 0.05 which is 0.021, so the null hypothesis is rejected at 5% level of significance. There is sufficient evidence to saistianiysighn rcamt.a2 The reu is