Question

2. A very long, straight wire runs from west to east. The wire is 17 m long and carries a 2.6 A current that moves from west to east. a. Earth's magnetic field is approximately uniform, and is directed from south to north. At the location of the wire, the magnetic field has the strength 4.4 x 10-5 T. Calculate the magnitude and direction of the force that Earth's magnetic field applies to the wire. b. What is the magnitude and direction of the magnetic field at a point 6.0 mm to the north of the wire due to the wire's current? C. What is the magnitude and direction of the total magnetic field 6.0 mm to the north of the wire due to the current in the wire and Earth's magnetic field?

Answer 1

answer MIN V - 11m Be - Magnetic field clue to earth Given 1 - 2.6 A. l = 17 m Be : 4.4 x 101 a) This can be solved using the equation, . F : Il B sino Also & given current flows from east to west and magnetic field from south to nosth. o 90° sy FE 2.6x17x4.4x10" sin 90 : - 5 8 71.945 x10°N - vo n due to the Direction of force will be perpendicular to both Current (1) and magnetic field. According to right Cstrumbe ruleth the force will direct out of the paper CamScanner

b) Magnetic field due to a straight current carrying conducto 32 Mo I 2017 Given ; I. 26 A in 6 mm = ex roºm. B'MO 4 it vro'x 216 POTY 211 x 6 x 10 - 2 x 10 x 2.6 - 6x 10-3 - 5 B' . $.67x10° Direction will be bach of the papes. . 1) At the point 6 mm away from conductor, the magnetic field due to current carrying .conductor into cects in the direction but of the paper. And magnetic field due to earth is soeuth to north. ie. They are perpendicular: ies @ = 90°. Resultant magnetic field; Ba| BT+ B.? + 2 B' BE.COSO B = B²+ Be² (cos o cos90 = o) .) (8-67810*3)* + (4.4x10%)? = 9.72 x10 ST Scanned with CamScanner