Question

Let pn = (an+bn)/2 , p = limn→∞pn, and en = p−pn. Here [an,bn], with n...

Let pn = (an+bn)/2 , p = limn→∞pn, and en = p−pn. Here [an,bn], with n ≥ 1, denotes the successive intervals that arise in the Bisection method when it is applied to a continuous function f.

Show that |pn −pn+1| = .2^{-n-1}(b1-a1)

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Prantben, keranston ant t I bisection method, Either, [ann, bron] = [an, Pn] or, [and, but] = [en, bu] Case I [anos, buri] =11Pn-Pasil = Ibn-an) 4 Case I [ant, bad]=[Pn, br] > ant=Pn= anton e bur= bn • Ano-an-an-bn, bir-bn ao an- anos + on-tomon lan2 So in both cases 6 & Tipo - Pao) = 16.2 mm - We also know that in binction method, lant-Bonoll - I An-bnl 1an-1-bm-11 lan-blan-bal= 18,-a, 1 substitute in Ibn-Pnel = 10,-a, 1 4.27 » IPn-PnHl= 2h-10/6-911

Add a comment
Know the answer?
Add Answer to:
Let pn = (an+bn)/2 , p = limn→∞pn, and en = p−pn. Here [an,bn], with n...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT