Firstly arrange the data in ascending form as follows :
21 |
22 |
22 |
24 |
24 |
25 |
26 |
26 |
26 |
28 |
28 |
29 |
29 |
31 |
32 |
33 |
34 |
34 |
34 |
37 |
37 |
38 |
38 |
38 |
83 |
The sample mean is 31.96 and standard deviation is 11.95 (pls note degree of freedom is 24)
For Dixon ration calculate the ratio R22 = Xn - X n-2 / Xn - X3 = 83-38 / 83-22 = 0.73
The critical value for this ratio is 0.46 at 5% level of significance. As 0.73 > 0.46 the null hypothesis is rejected that there is no outlier. 83 is thus the outlier.
For the Grubb test calculate G = Max I X - Sample Mean I / Standard deviation
The maximum value that is got is 4.27113 when X is 83. The critical value for this is 2.82 when n=25.
As 4.27 > 2.82, the null hypothesis is rejected.
NB
The data needs to be checked for normality first before these tests can be done. I have assumed normality.
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