Choose the best answer: S. dx X V16-9x2 In|csc cot | + C 2 n|csce cot...
Evaluate the following: csc(x) cot(x) dx i) s 2-csc (x) ii) S x sin(4x) iii) 6. x sin(x2) dx iv) x x + 3y = 3
s više dx V16 – x2 -√16 – x² x' +C V16 – x2 2x +C V16 - x² + c 16 - x2 2x +C 1 point 5 x2 dx = x3 +4 In | x3 + 4[ + C In [x] + + +C O In | x3 +41 whe in* +4 +C + 4x|+C
Please evaluate : 12* ∫ { [ cot (3X) ] ^4 } *{ [ csc (3X) ] ^2 } *dX as X varies from 0 radians to (π/12) radians
Evaluate the integral. Hot yet answered V2/2 larked out of 1.00 x dx v16 - x4 Flag question A) 0.0626 B) 0.1253 C) 1.1253 D)0.2506 Select one: 1.B o 2. A 3. C 4.D Finish attem Previous page
On the back, prove the identity: tan^3(x)csc^2(x)cot^2(x)cos(x)sin(x)=1 Use only the left side and try changing everything to sine and cosine. Original Question Image: On the back, prove the identity: tan'(r)csc(r)cot'(x)cos(x)sin(r)-1 Use only the left side and try changing everything to sine and cosine.
plzz help (1 point) Simplify each expression. (csc(t) – 1)(csc(t) + 1) = cot?(t) (sec(t) – 1)(sec(t) + 1) = (1 – sin(t))(1 + sin(t)) = cos? (t) (1 point) Simplify the expression as much as possible. 1 - sin(t) Ti n ( = help (formulas) (1 point) Match the functions with their graphs. 1. f(x) = cos(x) 2. f(x) = sin(x) 3. f(x) = tan(x) 4. f(x) = arcsin(x) 5. f(x) = arccos(x) 6. f(x) = arctan(x)
Differentiate. #’s 1,3, and 5 please 5.S LALT 1-16 Differentiate 2. f(x) = x cos x + 2 tanx 1. f(x) = x2 sin x 3. f(x)ecos x 2 sec x 4. y csC x 6. g(0)= e'(tan 0 e) 5. y = sec 0 tan 0 cot t 5.S LALT 1-16 Differentiate 2. f(x) = x cos x + 2 tanx 1. f(x) = x2 sin x 3. f(x)ecos x 2 sec x 4. y csC x 6. g(0)=...
u-substitution: indefinite integrals (In x)2 = dx = х Choose 1 answer: @ (In x)2 + C 2 In x + C (In x)3 3 +C © (In x)3 + C
Indefinite integrals. Use table 5.6 or a change of variables to evaluate the following indefinite integrals. check your work by differentiating. 2. 1 dx, x 2 32 xV4x2-I Table 5.6 General Integration Formulas cos ax C a sin ax C 1. cos ax dx = 2. sin ax dr se' 3. 4. ax dx=- ax dx -tan ax C a cot ax C 1 sec ax tan ax dx=-sec ax C 1 --csc ax C csc ax cot ax 5....
Please answer with work Find the most general antiderivative. 11) S (3x3 - 3x +8)dx 11) A) 9x2 - 3+ C B) 3x4 - 3x2 + 8x + c c) * *4- 2x2 +8 8x + C D) 9x4 - 6x2 + 8x + c