Question

อง R3 รี h

Suppose R1=4Ω, R2=2Ω, R3=8Ω, R4=10Ω, 5=6Ω, R6=16Ω, E1=9V and E2=11V.

Part A:

Use Kirchhoff's voltage law to find an equation for the voltage drop around loop 3

Part B:

Find the loop currents i1i1, i2i2 and i3i3 (positive for clockwise direction)

Part C:

Which direction does current flow across each of the resistors? Match with the following choices.

Possible choices :

A:from left to right
B: from right to left
C: no current

D: from top to bottom
E: from bottom to top
F: no current

Answer 1

( 1 ) R, - у -- Є, - PRR - 16- ) Само в 4 Кап- Apply kol in Loop - 3 – ч*+ 16 ( i-ii) + 2 ( 14-і) - о - чя ( + го і, -1°і, + 1 із - зі - о 165, -2, - 19із - 8 -0 Reely кои іn Toър - п. 2(1-1) - 6 ( -2) – від - 1 – 1, +2, + ві, - 11 + 16 - «і, - у - гу Kuz in loop- '31 - "ti - і, ) - 1 і, - «(і, - ка) - - заізмі, хід - о ві, + ci, - 34 с. - о - 13/

by solving equation ,1,2,3 find current in each loop current i1=1amp, i2 =1amp,i3=0.5amp

now by see the result we can verify option correctly

for R, current flow l, = 1 Amp left to right. meats current How from I gh Ra, current a lg-ii=1-1-0 No current flow gn R3, current ig = 1 Amp , current flow from Right to left In ry. Current Izri,-0.5-12-12 means current flow from Right to left. I Inrs, current - current q-iz aidata flow from Right to left gh R6, current 53 How means current flow F3 = 1 from Tup to bottom.