A basketball player sinks 50% of the 1500 shots he takes at the basket over a...
A basketball player sinks 50% of the 1500 shots he takes at the basket over a season. In the next season, he sinks 48% of the 1260 shots at basket. What is the probability that the performance in season 2 is better than that in season 1?
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A basketball player sinks 50% of the 1500 shots he takes at the basket over a season. In the next season, he sinks 48% of the 1260 shots at basket. What is the probability that the performance in season 2 is better than that in season 1?
We have to find P( p2>p1) = P( p2-p1)>0
P= P( z=((p2-p1)/se >0) = P( z >-1.047)
P=0.8524
|
Hypothesis test for two independent proportions |
|||||
|
P2 |
P1 |
pc |
|||
|
0.48 |
0.5 |
0.4909 |
p (as decimal) |
||
|
605/1260 |
750/1500 |
1355/2760 |
p (as fraction) |
||
|
604.8 |
750. |
1354.8 |
X |
||
|
1260 |
1500 |
2760 |
n |
||
|
-0.02 |
Proportion difference |
||||
|
0. |
hypothesized difference |
||||
|
0.0191 |
std. error |
||||
|
-1.047 |
z |
||||
|
.8524 |
p-value (one-tailed, upper) |
||||
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