Let the angle that the hub makes with the vertical be x.
Then the horizontal and vertical distances of the cm from the point where the hub is connected to the arm are 1*sin(x) and 1*cos(x) respectively.
Then the horizontal and vertical distances of the cm from the hing are (5+1*sin(x)) and 1*cos(x) respectively.
With an angular speed of 4 rad/s, the centrifugal force on the hub is
where m is the mass of the hub, is the angular velocity and R is (5+1*sin(x))
The vertical force is graviational force given by
The torque balance about the point where the hub is connected to the arm gives:
The anglis is 84.166° with the vertical
av = g = 9.8 m/s2
The acceleration values on the person would be same as the ones on the hub as the person is placed at the cm of the hub
So, the total acceleration experienced by the person is
acceleration is 96.4165 m/s2
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