Question

mize the functi 2x + 2y = 1 19. Explain why it is impossible to maximize z = 3x + 4y subject to the constraints x + y 28 2x + y = 10 x + 2y = 8 + > 0, y = 0. mize the function 20. Explain why it is impossible to maximize the z = 4x + 7y subject to the constraints 8y + 5x 2 40 4y + 9x = 36 11y + 2x = 22 x = 0, y = 0.

Answer 1

Lolulion маши и subject to 2 = 3х +4y X+47,8 2x + 4 = 10 x + 24 =8 u710, 470 The region is graphed by |x+2y = 8 ***y=80 is since there is no No Feasible region, thus common region, hence there manimum does not exist.

L 20 . 2=42+74 Subject to 84 +5 x 7,40 tan 536 I lly+2x €22 ,470, 470 The region is graphed by uuta4= 2x+lly = 2 Again region since is - 8x+6y=40 there is no common region, this NOT feasible. Hence, no maximum enists common region, thus the

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