Here , for the object between 1 and second position
displacement = 15.704 - 8.9 = 6.804 m
time taken = 53.90 - 52.50 = 1.4 s
Now, let the constant acceleration is a
and the initial velocity at the first location is u
Using second equation of motion
displacement = u * t + 0.50at^2
6.804 = u * 1.4 + 0.50 * a * 1.4^2 -----(1)
Now, between position 1 and 3
displacement = 26.036 - 8.9 = 17.136 m
time taken = 55.3 - 52.50 = 2.8 s
and the initial velocity at the first location is u
Using second equation of motion
displacement = u * t + 0.50at^2
17.136 = u * 2.8+ 0.50 * a * 2.8^2 ----(2)
solving equations 1 and 2
u = 3.6 m/s
a = 1.8 m/s^2
the constant acceleration is 1.8 m/s^2 at all times
An object is moving in a straight line with a constant acceleration. Its position is measured...
The position of an object moving along a straight line is given by where s is measured in feet and t in seconds. Find the velocity v(t) and acceleration a(t) of the object after 3 sec. (Round your answers to three decimal places.) ft/sec ft/sec2 a(3) The position of an object moving along a straight line is given by where s is measured in feet and t in seconds. Find the velocity v(t) and acceleration a(t) of the object after...
(ii)(a) An object is moving with constant acceleration in 1D (along a straight line), what is its position x(t) as a function of time, given its initial position xo, initial velocity vo and acceleration a? (b) How do you derive its velocity as a function of time from x(t)? (c) Why is the funciton of x(t) the key for predicting eclipses and hurricanes?
The velocity in mm/s of an object moving on a straight line is 200 multiplied by s (s given in mm). If the starting point at time zero is s = 0.5m, what is its acceleration when s = 2m and the time required to reach this position. 4. The velocity in mm/s of an object moving on a straight line is 200 multiplied by s (s given in mm). If the starting point at time zero is s time...
6.1.35 Find the position and velocity of an object moving along a straight line with the given acceleration, initial velocity, and initial position. a(t)= cos xt, v(0) = 4, s(0) = 1 The velocity is v(t)- Type an exact answer.)
Find the position and velocity of an object moving along a straight line with the given acceleration, initial velocity, and initial position. a(t)= -0.06, V(0) = 3, and s(0) = 0 v(t) = (Round to four decimal places as needed.) s(t)=0 (Round to four decimal places as needed.)
Find the position and velocity of an object moving along a straight line with the given acceleration, initial velocity, and initial position. a(t) = -0.01, v(0) = 4, and s(0) = 0 v(t) =D (Round to four decimal places as needed.) s(t)= (Round to four decimal places as needed.)
o Find the position and velocity of an object moving along a straight line with the given acceleration, initial velocity, and initial position a(t) = -0.06t, v(0) = 6, and s(0) = 0 v(t)=0 (Round to four decimal places as needed.) s(t)=0 (Round to four decimal places as needed.)
The position of an object moving in a straight line is given by the following formula where s is in meters and t is the time in seconds the object has been in motion. f[ s = 2t^2 - 3tf] How long (to the nearest tenth) will it take the object to move 9 meters?
4. In Chapter 1, we showed that for an object moving along a straight line with position function s(t), the object's "average velocity on the interval [a, b is given by s(b) s(a) More recently, in Chapter 4, we found that for an object moving along a straight line with velocity v(t), the object's “average value of its velocity function on [a, bl" is v(t)dt Are the 'average velocity on the interval a, b" and the "average value of its...
An object is moving along a straight line, and the uncertainty in its position is 3.60 m. (a) Find the minimum uncertainty in the momentum of the object. Find the minimum uncertainty in the object's velocity, assuming that the object is (b) a golf ball (mass = 0.0450 kg) and (c) an electron. (a) (b) (c)