Question

Problenz 24 The area of the Greek cross is 90 dm2 Determine the area and the perimeter of the square tha? contains it.

Answer 1

Area of the Greek cross = 90 dm^2 To find: Area and perimeter of the square that contains it. From figure, we can see that the square that contains the Greek Cross is made up of nine equal small squares having equal areas and the Greek Cross is made up of the same five small equal squares having equal areas. Now, As the Greek Cross is made up of five equal small squares, Therefore Area of each small square = Area of Greek Cross/5 = 90/5 dm^2 = 18 dm^2 As the square that contains the Greek Cross is made up of nine equal small squares Therefore Area of the square that contains the Greek Cross = 9 times Area of one small square = (9 times 18) dm^2 = 162 dm^2 Length of the side of the square that contains the Greek Cross = squareroot Area = squareroot 162 dm = 9 squareroot 2 dm