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2. A manufacturer of replacement bulbs for LCD projectors claims a 1000 hour average life time for the bulbs. This is importa
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Answer #1

Solution:

Here, we have to use one sample t test for the population mean.

H0: µ = 1000 versus Ha: µ ≠ 1000

This is a two tailed test.

We are given

Level of significance = α = 0.05

From given data, we have

n = 12

Xbar = 977.8333333

S = 23.40098418

df = n – 1 = 11

Critical values = - 2.2010 and 2.2010

(by using t-table)

Critical Region: Reject H0 if t < - 2.2010 or t > 2.2010

Test statistic is given as below:

t = (Xbar - µ)/[S/sqrt(n)]

t = (977.8333333 – 1000) / [23.40098418/sqrt(12)]

t = -3.2814

P-value = 0.0073

(by using t-table)

P-value < α = 0.05

Test statistic = t = -3.2814 < critical value = - 2.2010

So, we reject the null hypothesis

There is insufficient evidence to conclude that the average life time for the bulbs is 1000 hours.

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