Solution:
Here, we have to use one sample t test for the population mean.
H0: µ = 1000 versus Ha: µ ≠ 1000
This is a two tailed test.
We are given
Level of significance = α = 0.05
From given data, we have
n = 12
Xbar = 977.8333333
S = 23.40098418
df = n – 1 = 11
Critical values = - 2.2010 and 2.2010
(by using t-table)
Critical Region: Reject H0 if t < - 2.2010 or t > 2.2010
Test statistic is given as below:
t = (Xbar - µ)/[S/sqrt(n)]
t = (977.8333333 – 1000) / [23.40098418/sqrt(12)]
t = -3.2814
P-value = 0.0073
(by using t-table)
P-value < α = 0.05
Test statistic = t = -3.2814 < critical value = - 2.2010
So, we reject the null hypothesis
There is insufficient evidence to conclude that the average life time for the bulbs is 1000 hours.
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