when a 99% confidence interval is calculated instead of a 95% confidence interval with n being the same, the margin of error will be larger, smaller, the same, or cannot tell because it depends on other information as well?
when a 99% confidence interval is calculated instead of a 95% confidence interval with n being...
19. The 99% confidence interval is _________ than 95% confidence interval in a same problem. a. smaller b. larger 20. Suppose 95% confidence interval of the population mean is (4.5, 9.7). (20.a) The population mean must be in the range (4.5, 9.7). a. True b. False (20.b) What is the chance of error if you say that the population mean is somewhere in the range (4.5, 9.7) a. 0.95 b. 0.05 c. 0 d. 0.5 (20.c) How sure is it...
What would happen (other things being equal) to a confidence interval if you calculated a 99% confidence interval rather than a 95% confidence interval? Question 11 options: It will not change. It will be wider. It will be narrower.
Find the margin of error for a 95% confidence interval for estimating the population mean when the sample standard deviation equals 92, with a sample size of (a) 400,(b) 1800. What is the effect of the sample size? 2. The margin of error for a 95% confidence interval with a sample size of 400 is (Round to the nearest tenth as needed.) b. The margin of error for a 90% confidence interval with a sample size of 1600 is (Round...
1) Find n for a 99% confidence interval for p with bound on the error of estimation (margin of error) = 0.03 using an estimate of p = 0.85. (Round up to the nearest whole number.) 2)Find the conservatively large value for n using the same confidence interval and bound on the error of estimation (margin of error) mentioned in part a with no estimate of p. (Round up to the nearest whole number.)
Determine the margin of error for a 95% confidence interval to estimate the population mean when s=37 for the sample sizes below. Solve for c) n=46. htmathe Student Homework Theme =41778etod y FALL 2019 STAT 3309 CRN 120961 Homework: Section 8.3 Confidence intervals with s Homework Score: 0 57 of 1 pt 28.3.22-T Determine the margin of error for a 95% confidence interval to estimate the E a) n. 13 b) n = 30 c) n46 a) The margin of...
A 95% confidence interval for a population mean was calculated. The sample mean was found to be 34.5 and the MOE was found to be 4.06 giving us a confidence interval of 34.5±4.06 or equivalently written as 30.44 to 38.56. (a) For the hypotheses H0:?=30 Ha:??30, would you reject the null hypothesis at the 5% level of significance (i.e. ? = 0.5)? (Type: YES or NO or CANNOT TELL): (b) For the hypotheses H0:?=41 Ha:??41, would you reject the null...
When we decrease the sample size, what happens to the margin of error in the confidence interval? A. Become larger B. Become smaller C. Stay the same D. It depends
You collect a random sample of size n from a population and calculate a 98% confidence interval. Which of the following strategies produces a new confidence interval with a decreased margin of error? A.) Use a 99% Confidence level B.)Use a 95% confidence level C.)Decrease Sample Size D.)Use the same confidence level but compute the interval n time. Approximately 2% of these intervals will be larger. E.)Nothing can guarantee that you will obtain a larger margin of error. You can...
Determine the sample size n needed to construct a 99% confidence interval to estimate the population mean when σ=33 and the margin of error equal 5 n=?
To calculate a confidence interval, the margin of error (E) must first be calculated. The Margin of Error, E, for means is: E = 1.96*s/sqrt(n), where s is the sample standard deviation, n is the sample size. The “sqrt” stands for square root. The Margin of Error, E, for proportions is: E = 1.96*sqrt[p*(1-p)/n], where s is the sample standard deviation, n is the sample size, and p is the proportion. Use the Confidence Interval formula above, and the correct...