how much oxygen is needed ( in L, at 218.0 degrees C, 5.35 atm) to completely...

Question

Question

how much oxygen is needed ( in L, at 218.0 degrees C, 5.35 atm) to completely burn 10 moles of propane (C3H8)?

Answer 1

Answer #1

C3H8 + 5(O2) → 4(H2O) + 3(CO2)

is the balanced equation

so,1 mole propane reacts with 5 moles of O2 to form products

hence,

for 10moles of propane to burn completely we need 5*10 =50 moles of O2

Using

PV=nRT

5.35atm* V = 50 * 0.0821 * (218+273)

v= 376.74L

Answer 2

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