Question

08 Question (1 polnt) TLAUNCH TUTORIAL LESSON COAST Tutorial Problem Given the following reactions: 2D Kc-5.32 x 104 KC = 5.53 ×102 D-2A+2B 1st attempt See Periodic Tab Calculate the value of the equilibrium constant for the following reaction. 〈 0823 17 OF 23 QUESTIONS COMPLETED m1120p2 (8) .pdf m1120p2 (7)pdf m1120p2 (6)pdf

Answer 1

2C ---> D

Kc1 = [D] / [C]^2

D ---> 2A + 2B

Kc2 = [A]^2 [B]^2 / [D]

now

A + B ---> C

Kc3 = [C] / ( [A] [B] )

comparing Kc1 , Kc2 and Kc3

a relation can be obtained as below

Kc3 = 1 / sqrt (Kc1 x Kc2)

Kc3 = 1 / sqrt (5.32 x 10-4 x 5.53 x 10-2)

Kc3 = 184.37

so

the value of equilibrium constant for the required reaction is 184.37