Claim: less than 10% of the results are wrong.
n = sample size = 300
x = number of wrong test result = 27
level of significance = 0.05
Let's write null and alternative hypothesis as
null hypothesis is H0 : P= 0.10
and alternative hypothesis is H1 : P < 0.1
We can used one sample proportion z test.
Using minitab.
The command for one sample proportion z test in minitab is
Stat>>>Basic statistics>>>1-proportion...
Then click on summarized data
number of events = x = 27
Number of trials = n = 300
Click on "Perform hypothesis test
Hypothesized proportion = P = 0.1 (because under the null hypothesis P = 0.1)
then click on option
Level of confidence in percentage = c = ( 1- )*100 = = (1 -0.05)*100 = 95.0
so put "Confidence level " = 95.0
Alternative = less than
then click on "Use test and interval based on normal approximation"
Then click on OK and again click on OK
So we get the following output
From the above output, we get
test statistic value , Z = -0.58
P-value = 0.282
Decision rule:
1) If p-value < level of significance (alpha) then we reject null hypothesis
2) If p-value > level of significance (alpha) then we fail to reject null hypothesis.
Here p value = 0.282 > 0.05 so we used 2nd rule.
That is we fail to reject null hypothesis
Conclusion: At 5% level of significance there are not sufficient evidence to say that the sample data indicates less than 10% of the results are wrong.
So the test may no appear to be good for most purpose.
please answer question and show all steps. thank you :) Los Angeles & Marijuana Marijuana refers...
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