u= 24
f=10
h = 2.52
applying mirror formula
1/v + 1/u = 1/f
v= f*u/(u-f)
=17.142 cm ( distance of image from the vertex)
m=- v/u = h'/h ( magnification)
so h' = -v*h/u= 17.142*2.52/24 = 1.8 cm
image will be inverted and diminished
object distance u = 24 cm
f = 10 cm
object height y= 2.52 cm
from the relation
1/u + 1/v = 1/f
1/24 + 1/v = 1/10
v = 17.142 cm
as image distance is +ve it is real image
and magnification m=-v/u = y'/y
size of the image y' = -17.142*2.52/24 = -1.8 cm
as image height is -ve it is a inverted and enlarged image
distance from vertex v = 17.142 cm
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