i need help with the calculations from the first part of the
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i need help with the calculations from the first part of the
lab
Freezing Point Depression...
Part B. Initial Freezing Point of Water Mass of water Mass of Solute Molecular Weight of...
Part B. Initial Freezing Point of Water Mass of water Mass of Solute Molecular Weight of solute moles of solute kg of water in solution molality of solution Final Freezing Point of solution Change in Freezing Point kr from part A i for the solute(theoretical) i for the solute(experimental) NaCl 0°C 10.0 g 0.58 9 g/mole mole kg KCI oºch 10.0 g 0.75 g g/mole mole kg CaCl2 0°C 10.09 1.11 g g/mole mole kg m -5.6°C °c C/m -3.7°C...
Naci КСІ CaCl2 °C g Part B. Initial Freezing Point of Water Mass of water Mass...
Naci КСІ CaCl2 °C g Part B. Initial Freezing Point of Water Mass of water Mass of Solute Molecular Weight of solute moles of solute kg of water in solution molality of solution Final Freezing Point of solution Change in Freezing Point kr from part A i for the solute(theoretical) i for the solute(experimental) g/mole mole kg| m g g g/mole mole kg m g/mole mole kg m -37°C -3.7°C -55 °C °C "C/ml cl "C/m 'cl "Clm
molecular weight moles of solute kg owater insolution molality of solution change in freezing point Naci...
molecular weight
moles of solute
kg owater insolution
molality of solution
change in freezing point
Naci KCI CaCl, Initial Freezing Point of Water Mass of water Mass of Solute Molecular Weight of solute moles of solute kg of water in solution molality of solution Final Freezing Point of solution Change in Freezing Point kr from part A i for the solute(theoretical) i for the solute(experimental) 9 9 9 g/mole g/ mole mole mole kal kg m m -31°C 3 °C...
Molar Mass Determination by Freezing Point Depression Calculate and enter the freezing point depression of a...
Molar Mass Determination by Freezing Point Depression Calculate and enter the freezing point depression of a solution of 57.6 g ethylene glycol (C2H602) in 734 g H20. Kffor H20 is 1.86 °C kg/mol. °C -2.53 1 homework pts Submit Answer Incorrect. Tries 3/5 Previous Tries A solution which contains 71.9 g of an unknown molecular compound in 363 g of water freezes at -3.85°C. What is the molar mass of the unknown? g/mol 1homework pts Submit Answer Tries 0/5 Molar...
Molar Mass Determination by Freezing Point Depression Calculate and enter the freezing point depression of a...
Molar Mass Determination by Freezing Point Depression Calculate and enter the freezing point depression of a solution of 65.1 g ethylene glycol (C2H602) in 792 g H20. Kffor H2O is 1.86 °C kg/mol. °C 1homework pts Submit Answer Tries 0/5 A solution which contains 60.9 g of an unknown molecular compound in 325 g of water freezes at -3.24°C. What is the molar mass of the unknown? g/mol 1homework pts Submit Answer Tries 0/5
i need help using the formula in the 3rd picture , to figure picture 2(the molar...
i need help using the formula in the 3rd picture , to figure
picture 2(the molar mass). I included needed information in picture
1
Pure TBA, T9 Ethylene Glycol/TBA Solution, T Calculation of Molar Mass of Ethylene Glycol Mass of ethylene glycol used (total amount in solution) .94 253 t Mass of TBA used Freezing point of pure TBA, T Freezing point of solution, T, oC oc oC Freezing point depression (total dgpression), 471 Total molal concentration m of ethylene...
Need help with freezing point depression expeiment volume of acetic acid 30 volume of unknown solute...
Need help with freezing point depression expeiment volume of acetic acid 30 volume of unknown solute in solution1 1.5 volume of unknown solute in solution 2 1.5 freezing point of pure acetic acid 16.3 freezing point of solution 1 14.5 freezing point of solution 2 11.3 average molar mass of unknown solute Calculations for Part 1 The density of acetic acid is 1.049 g/mL and Kf(acetic acid) =3.90 °C·kg/mol The density of the unknown is 0.791 g/mL. 1.Calculate the masses...
Post-Lab Material Experiment 19 Data and Calculations: Molar Mass Determination by Depression of the Freezing Point...
Post-Lab Material Experiment 19 Data and Calculations: Molar Mass Determination by Depression of the Freezing Point 0.3 Name Section A. Measured Freezing Point of Pure Water B. Finding the Freezing Point of a Solution of Liquid Unknown Target mass of solute (Calculated based on the parameters in the instructions) Unknown # Liquid 3.5 Actual mass of solute used Trial Freezing point of solution (observed) -3.0 Mass of solution 116.6 Trial II Freezing point of solution -3.3 Mass of solution 101.3....
Molar mass determination by depression of freezing point lab I'm stuck on calculating the moles of...
Molar mass determination by depression of freezing point lab I'm
stuck on calculating the moles of solute.. How do I calculate it?
Also can u please check if I've done everything else correctly..
The data I collected: Measured freezing point of pure water: 0.0
degrees Celsius Actual mass of solute used: 10.12g Freezing point
of solution (observed): -3.4 Celsius Mass of solution: 84.7g
Freezing point of a Solution of liqud unknown Freezing point depression: Trial #1. 0.0℃ (-3.4°C)= 3.4℃ Molality...
Calculate and enter the freezing point depression of a solution of 73.2 g ethylene glycol (C2H602)...
Calculate and enter the freezing point depression of a solution of 73.2 g ethylene glycol (C2H602) in 561 g H20. Kffor H20 is 1.86 °C kg/mol. °C 1homework pts Submit Answer Tries 0/5 A solution which contains 43.6 g of an unknown molecular compound in 339 g of water freezes at -4.85°C. What is the molar mass of the unknown? g/mol
Part B. Initial Freezing Point of Water Mass of water Mass of Solute Molecular Weight of solute moles of solute kg of water in solution molality of solution Final Freezing Point of solution Change in Freezing Point kr from part A i for the solute(theoretical) i for the solute(experimental) NaCl 0°C 10.0 g 0.58 9 g/mole mole kg KCI oºch 10.0 g 0.75 g g/mole mole kg CaCl2 0°C 10.09 1.11 g g/mole mole kg m -5.6°C °c C/m -3.7°C...
Naci КСІ CaCl2 °C g Part B. Initial Freezing Point of Water Mass of water Mass of Solute Molecular Weight of solute moles of solute kg of water in solution molality of solution Final Freezing Point of solution Change in Freezing Point kr from part A i for the solute(theoretical) i for the solute(experimental) g/mole mole kg| m g g g/mole mole kg m g/mole mole kg m -37°C -3.7°C -55 °C °C "C/ml cl "C/m 'cl "Clm
molecular weight
moles of solute
kg owater insolution
molality of solution
change in freezing point
Naci KCI CaCl, Initial Freezing Point of Water Mass of water Mass of Solute Molecular Weight of solute moles of solute kg of water in solution molality of solution Final Freezing Point of solution Change in Freezing Point kr from part A i for the solute(theoretical) i for the solute(experimental) 9 9 9 g/mole g/ mole mole mole kal kg m m -31°C 3 °C...
Molar Mass Determination by Freezing Point Depression Calculate and enter the freezing point depression of a solution of 57.6 g ethylene glycol (C2H602) in 734 g H20. Kffor H20 is 1.86 °C kg/mol. °C -2.53 1 homework pts Submit Answer Incorrect. Tries 3/5 Previous Tries A solution which contains 71.9 g of an unknown molecular compound in 363 g of water freezes at -3.85°C. What is the molar mass of the unknown? g/mol 1homework pts Submit Answer Tries 0/5 Molar...
Molar Mass Determination by Freezing Point Depression Calculate and enter the freezing point depression of a solution of 65.1 g ethylene glycol (C2H602) in 792 g H20. Kffor H2O is 1.86 °C kg/mol. °C 1homework pts Submit Answer Tries 0/5 A solution which contains 60.9 g of an unknown molecular compound in 325 g of water freezes at -3.24°C. What is the molar mass of the unknown? g/mol 1homework pts Submit Answer Tries 0/5
i need help using the formula in the 3rd picture , to figure
picture 2(the molar mass). I included needed information in picture
1
Pure TBA, T9 Ethylene Glycol/TBA Solution, T Calculation of Molar Mass of Ethylene Glycol Mass of ethylene glycol used (total amount in solution) .94 253 t Mass of TBA used Freezing point of pure TBA, T Freezing point of solution, T, oC oc oC Freezing point depression (total dgpression), 471 Total molal concentration m of ethylene...
Post-Lab Material Experiment 19 Data and Calculations: Molar Mass Determination by Depression of the Freezing Point 0.3 Name Section A. Measured Freezing Point of Pure Water B. Finding the Freezing Point of a Solution of Liquid Unknown Target mass of solute (Calculated based on the parameters in the instructions) Unknown # Liquid 3.5 Actual mass of solute used Trial Freezing point of solution (observed) -3.0 Mass of solution 116.6 Trial II Freezing point of solution -3.3 Mass of solution 101.3....
Molar mass determination by depression of freezing point lab I'm
stuck on calculating the moles of solute.. How do I calculate it?
Also can u please check if I've done everything else correctly..
The data I collected: Measured freezing point of pure water: 0.0
degrees Celsius Actual mass of solute used: 10.12g Freezing point
of solution (observed): -3.4 Celsius Mass of solution: 84.7g
Freezing point of a Solution of liqud unknown Freezing point depression: Trial #1. 0.0℃ (-3.4°C)= 3.4℃ Molality...
Calculate and enter the freezing point depression of a solution of 73.2 g ethylene glycol (C2H602) in 561 g H20. Kffor H20 is 1.86 °C kg/mol. °C 1homework pts Submit Answer Tries 0/5 A solution which contains 43.6 g of an unknown molecular compound in 339 g of water freezes at -4.85°C. What is the molar mass of the unknown? g/mol
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