Question

Problem 2: Now assume that a power of H = 3 kW is transmitted between the shafts and gears and the pressure angle of the bevel gears is ø= 20°. Then find: a) Contact forces between the helical and bevel gears b) Reaction forces at bearings C and D. Assume that the thrust forces are taken by the bearing D. m= 6, 32765 -16 m = 2. 12T. 23° F 38 mm) SXBja 540 rev/min 40T EI 27 35 50 30 30

Answer 1

Here is the solution of subpoint b.

12T, m=2, 23°4 540 rev/min - 40T, m=2, 2304 Reduction is as :- Input a Cear 2,3 Gear 4, s Coutout)

Assuming input speed 520 mm r = 21 T: 53051.6 Nmm. T= 53.05.16 rogresso peduction Speed @ Shaft bo- Torque @ shaft 6 i- P: 20 N TE 3768388 Nem 176.83 NO Calculation o reaction forces at bear 2 30 SO 309

first we will find helical gear. fore to f = 2000 T fi = tangential force da diameter of gear. d = m* T = 2*40=80mm mid T 1 Ft = 2000 * 176.83 80 Ft= 4420,75kN Fn = Ft tan B Here ß= helix angle in question it is & Fra Ft tanan Cos B given as B: 230 so Fx = Ft tan 23 Ex = 1876.5 KN !

for = F tando COSB angle for helical gear Normal pressure xoa 20 den = 1747.97 KN I FBD of shaft b.

fr = 1747.97 KN Fr*55 - 110Rc Rc = Fr *55 - 873.90 - 110 Re = 873.98 KN

Efyzo Ret RD = Fr R = Fr - Rc RD = 873,985 KN force bem Cannot helical calculate & bevel contact gear