Question

How do you solve both of these questions. please show all steps and charts

= hiche hz-ni 329 31 btn-2921 .1 od -6. .kz n h3 214.79-2779 3. Six-kilogram mixture of H, and N, has 50% of Hby volume. How much energy is N has 50% of Hby volume. How much energy is needed to raise the temperature from 300 K to 400 K at constant pressure? (in kJ) (a) 1290 (b) sou 1600 d) 1160 TC) 924 Answer. D For the crime s: Air with moisture in a tank is at 50 kPa and 50°C. It is also found that its dew TITY)

Answer 1

3.

mass of mixture = m = 6 kg Voleme of Hydrogen – Vw = 50% molecular weight of Hydrogen= MH2=2 .. weight of hydrogen = Vnx Minta FOO 2 = 1 gram i malecular weight of Niloogen = 28 .. weight of nitrogen = 50 x 28 = 14 gram 100 .. wt % of hydrogen is given as wty of hydsogens is X100 = 6.6664. Wt y of Nitrogen = 14 x100 = 93.333 %. so that mass of hydrogen= mua wty of hydoogen x m 6.666 x6 = 0.39996 Ka 100 mass of nitrogen = mna= Wty of nitrogen om = 93.333 100 x6 = 5.59998 kg x6 =

Specific heat of hydrogen and nitrogen are Cette = 14.549 kJ/kg.k CP Ne = 1.039 kJ/kg.k ... energy needed is given as E = [m ceCTz-T)]ms + [m<p (Ta-T.)] na = E= [0-39936 14-543x (400-300)] + [5.593980997 = E= 1163 ks so that obtion (d) 1160kJ is correct