You have 775 mL of an 0.49 M acetic acid solution. What volume (V) of 2.40...

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Question

Answer 1

Answer #1

Henderson-Hasselbalch equation

pH =pKa + log [(Base)/(acid)]

4.56 = 4.76 + log[(X)/(0.49)]

log[(X)/(0.49)] = -0.2, X = 0.3 M

we have 2.4M NaOH

Let us assume required volume of NaOH = x ml

2.4M NaOH xml = 0.3 x (775+x) = 232.5 + 0.3x

x = 110.71 ml

Answer 2

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