Consider a normal distribution curve where 80-th percentile is at 16 and the 45-th percentile is at 1. Use this information to find the mean, μ , and the standard deviation, σ , of the distribution.
a) μ=
b) σ=
here as we know that X =mean +z*sd deviation
for 80 th percentile ; z =0.8416
hence 16 =μ+0.8416*σ ..........(1)
for 45 th percentile: z =-0.1257
hence 1 =μ-0.1257*σ.............(2)
solving above
a)μ =2.95
b) σ= 15.51
Consider a normal distribution curve where 80-th percentile is at 16 and the 45-th percentile is...
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Consider a normal distribution with mean 25 and standard
deviation 5. What is the probability a value selected at random
from this distribution is greater than 25? (Round your answer to
two decimal places.)
Assume that x has a normal distribution with the specified
mean and standard deviation. Find the indicated probability. (Round
your answer to four decimal places.)
μ = 14.9; σ = 3.5
P(10 ≤ x ≤ 26) =
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