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(1 point) Consider a normal distribution curve where the middle 90 % of the area under the curve lies above the interval ( 3·

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Answer #1

a)
mu = ( 3 + 11)/2 = 7

b)
For 90% CI, z-value = 1.645

mu - z*sigma = 3
sigma = (7 - 3)/1.645
sigma = 2.4316

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