Question

QUESTIONS RELATE TO: HYDROCODONE

1. A.) Draw the expanded structural formula of HYDROCODONE (showing all atoms

and all covalent bonds).

If it contains atoms other than C or H add lone pairs of electrons to each until the octet rule is satisfied for that atom.

B.) Determine molecular geometry of each central atom.

C.) For each central atom decide if it is polar or non polar.

2. Illustrate all ways that hydrocodone molecule could form hydrogen bonds with water. Do this by drawing bent water molecules as necessary and use dashed RED lines (---) to show H-

bonding between water and the appropriate atom in the molecule. Be very clear which atoms on each molecule are involved in the hydrogen bonds.

Hydrogen bonds from water can only from to the polar parts of your molecule.

If your drug molecule is not capable of forming hydrogen bonds with water, fully explain why

not.

3. Calculate the molar mass hydrocodone (C18H21NO4) to the hundredth’s place

using the molar masses from the periodic table (include units). Clearly show the work for your molar mass calculation below.

4. Calculate how many molecules of hydrocodone are in 200.0mg.

You wish to prepare 50.0 mL of 2.30 x 10^2 M solution of your drug.

5. Calculation. (hint- how many grams will you need of hydrocodone?)

6. Describe how to prepare this solution from the pure drug and deionized water.

Analytical balances and volumetric flasks are available to you. (Assume that your

drug dissolves in water, at least to the extent necessary for this problem.) Use

complete sentences in your description of the solution preparation process.

7. A patient is given 2.0mL of a 3.00% (m/v) solution of hydrocodone, how many milligrams

did they receive?

8. What is the molarity of a 3.00% (m/v) solution of hydrocodone?

Answer 1

I t-ó-ö -ZI ISO Expanded structure of Hydrocodone: A CH3

sp CH sp3: tetrahedral sp2: trigonal planer P: polar NP: non-polar Spa CH sp2 NP Сн O=0 0-0 C) Any carbon atomattached to hetero atom such as N or O becomes polar and rest of the atoms are relatively non-polar. Spa No to go Togola IN spo INP 0-0 CH NP

2) In the hydrocodone molecule the hetero atoms act as an acceptors in hydrogen bonding as they have lone pair of electrons on each. For simplification I am using simple bond-line formula. CH3 0-H----;00 O-H---:0: O-H--- 1 CH2 O-H 3) Molecular formula of hydrocodone is: C18H21NO3 Consider, atomic mass of C = 12.0107u, H = 1.00794u, N = 14.0067u, O = 15.9994u Molecular weight = (18*12.01)+(21*1.01)+(14.01)+(3*16.00) = 299.40 g/ mol

4) mass of hydrocodone = 200.0 mg = 200.0*10^-3 g Number of moles = mass / molar mass = (200.0*10^-3g)(299.4g/mol) = 0.6680*10^-3 mol Each mole contains 6.022*10^23 molecules. Then 0.6680*10^-3 mol of hydrocodone will contain = 0.6680*10^-3 mol *6.022*10^23 = 4.0227*10^20 molecules. Thus 200.0mg of hydrocodone will contain 4.023*10^20 molecules. 5) Required: 50mL of 2.3*10^2 M solution Number of moles in 1000mL = 2.3*10^2 mol then number of moles of hydrocodone in 50mL = (50*2.3*10^2)/1000 = 11.5 moles Mass of 11.5mol = 11.5mol * 299.4g/mol = 3443.1 g Thus to prepare required solution we need to disolve 3443.1g of hydrocodone in 50mL solvent. 6) i) Weigh accurately 3443.1 g of hydrocodone and transfer it to the dry 50mL volumetric flask directly. ii) add 25mL of distilled water to the flask and shake the flask till every thing disolves. iii) add ditilled water upto the mark of volumetric flask. This will give given 50mL solution.

7)

3.00% m/v solution contains = (mass / volume of solution)*100

Thus in 2.0mL solution mass of hydrocodone = (3/100)*2.0 = 0.06 g = 60 mg

Thus patient received 60 mg of drug.

8)

The number of moles of hydrocodone = 0.06g / 299.4g/mol = 2.004*10^-4 mol

this is number of moles in every 2.0mL

then for 1000mL the number of moles = (1000*2.004*10^-4)/2 = 0.1002 moles

So the molarity of the solution is = 0.1002 M = 0.100 M 3 sig. fig.