Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.)
μ = 103; σ = 14
P(x ≥ 120) =
Solution :
Given that ,
mean = = 103
standard deviation = = 14
P(x 120) = 1 - P(x 120)
= 1 - P[(x - ) / (120 - 103) / 14]
= 1 - P(z 1.2143)
= 1 - 0.8877
= 0.1123
P(x 120) = 0.1123
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