Question

M5.8 Rigid bar with opposing members scenes the internal forces and normal stresses bars (1) and (2). (+ = tension, - = compression) Bar properties Also, determine the deflection of the rigid bar in the A = 400 mm? x direction at C. E = 100 GPa 400 mm A2 = 400 mm? Ez = 100 GPa (2) F. (kN) 510 mm FkN - 70 KN (MPa) 680 mm 02 (MPa) 500 mm 510 mm ve (mm) Try one 1 2 3 attempt enter A Philpot 2004-2017

Answer 1

k TokN yao mm 510mm AI=Az = A=400 mm ck 70KN G=E₂=E=100 GPa 1680mm E=105mpa B 500mm of 4 = 50omm Slomm L2 - 400 mm >x -An for equilibrium EMA=0; F2 x 1700 - 70x1190 + Fix s10=0 10 F2+3 Fi = 490 - (1) Slom A slo compatibility, Taco - 146 - 46 - AB=0.34, FILE = (1 52 22 0.3 680mm 5 lomm AA F2 = HILI - Fix 500 0.3 x 400 Ex: 25 )

from equation i, & in 16 x 25 F 1 + 3 F1 = 480 IF = 10.970 KN (Tension) from equation (iii) F2 = 25x10.97 = 45.709 KN F2 = -45.709 KN (compression) 51 = = 10.970% 10% 10.970x16 400 Nimm² or mpa 101= 27.425 mpal ( Tensile) 02= f = F = - 45.709X163 Αν 400 102=-114.2725 mpa (Compressive)

from equation (11) A c = 1190 1700 -0.7AB= 6 1 F2 L2 l A2G Ac07 02 - Sax (-14:27 28 ) x 400 105 Ae=-0.320 mm Negative x-doreed on)