Given an array and a starting position write a function replaceFromN, that takes an integer array 'array', the size of the array size and a starting positions 'n' as parameters and replaces the elements starting from that index onward with the sequence 1,2,3,... The function returns nothing.
void replaceFromN(int array[], int size, int n)
For example, given
array= {15,12,4,9,2,3}
n =2
the function should modify array to be {15,12,1,2,3,4}
#include <iostream>
using namespace std;
// Function declaration
void replaceFromN(int array[], int size, int n);
int main()
{
// Declaring an array
int array[] = { 15, 12, 4, 9, 2, 3 };
// Displaying the elements of an array
cout << "Displaying the elements in the array before
replacing :" << endl;
for (int i = 0; i < 6; i++)
{
cout << array[i] << " ";
}
/* calling the function by passing
* array,size,index val as arguments
*/
replaceFromN(array, 6, 2);
return 0;
}
/* This function will replace the
* elements of an aray from the index n
* with sequence of values
*/
void replaceFromN(int array[], int size, int n)
{
int seq = 0;
for (int i = 0; i < size; i++)
{
if (i >= n)
{
array[i] = ++seq;
}
}
// Displaying the elements of array
cout << "\nDisplaying the elements in the array after
replacing :" << endl;
for (int i = 0; i < size; i++)
{
cout << array[i] << " ";
}
}
__________________
Output:
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Given an array and a starting position write a function replaceFromN, that takes an integer array...
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