Question

Write a function named numPerfect that takes as parameters:

an array of integer scores between zero and 100 (inclusive)

the size of the array

and returns the number of perfect scores in the array.

Also write a main function that creates and initializes an array of ints (in the appropriate range), calls the function with that array, and prints out the return value.

Answer 1

#include <iostream>
#include <iostream>
#include <iomanip>
using namespace std;

// Function Declarations
bool is_perfect(int num);
int numPerfect(int arr[], int size);

int main()
{
// Declaring varaibles
int i = 0, size, num, tot;

// Getting the size of an array
cout << "Enter the size of an array :";
cin >> size;

// Creating integer array dynamically based on size
int* arr = new int[size];

/* Getting the numbers entered by the user
* and populate those values into an array
*/
while (i < size)
{
cout << "\nEnter the number#" << i + 1 << ":";
cin >> num;
if (num < 0 || num > 100)
{
cout << "Invalid .Number must be between 0-100" << endl;
continue;
}
else
{
arr[i++] = num;
}
}

tot = numPerfect(arr, size);
cout << "Total No of Perfect Numbers in the array :" << tot << endl;
return 0;
}

int numPerfect(int arr[], int size)
{
int count = 0;
for (int i = 0; i < size; i++)
{

if (is_perfect(arr[i]))
{
count++;
}
}
return count;
}

/* Function implementation which checks
* whether the user entered number is perfect or not
*/
bool is_perfect(int num)
{
// Declaring the variable
int sum = 0;

for (int i = 1; i < num - 1; i++)
{
if (num % i == 0)
sum += i;
}

/* if the user entered number is equal to the
* sum value the number is perfect number
*/
if (sum == num)
return 1;
else
return 0;
}

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Output:

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