Question

Write a function named findTarget that takes three parameters:
- numbers, an array of integers
- size, an integer representing the size of array
- target, a number
The function returns true if the target is inside array and false otherwise

Answer 1

ANSWER:-

#include <iostream>
using namespace std;
bool findTarget(int arr[],int n,int t);

int main(){
int num,t;
bool flag;
cout<<"enter teh size of array : ";
cin>>num;
int arr[num];
cout<<"enter elements of the array : ";
for(int i=0;i<num;i++)
cin>>arr[i];
cout<<"enter target number : ";
cin>>t;
flag = findTarget(arr,num,t);
if (flag==true)
cout<<t<<" is available in array !";
else
cout<<t<<" is not not available in array !";
return 0;
}
bool findTarget(int arr[],int n,int t){ // question reqirement function
for(int i = 0; i < n; i++) {
if(t == arr[i]) {
return true;
break;
}
}
return false;
}

// OUTPUT

Success #std in #stdout 0s 4512KB enter teh size of array 5 enter elements of the array 6 9 2 18 enter target number: 1 1 is available in array!

// Please vote