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1. Write a function named findTarget that takes three parameters: numbers, an array of integers - size, an integer representi
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Answer #1

#include <bits/stdc++.h>
using namespace std;

int fillAndFind(int a[], int n)
{
   cout<<"Enter "<<n<<" value in the array: \n";
   int c=0;
   for(int i=0;i<n;++i)
   {
       cin>>a[i];
       if(a[i]%2!=0)
           c++;
   }
   return c;
}

bool findTarget(int a[], int n, int t)
{
   for(int i=0;i<n;++i)
   {
       if(a[i]==t)
           return 1;
   }
   return 0;
}

double minValue(double arr[], int n)
{
   double m=100000.0;
   for(int i=0;i<n;++i)
   {
       if(m>arr[i])
           m=arr[i];
   }
   return m;
}

int main()
{
   int n;
   cout<<"Enter the size of the array you want: ";
   cin>>n;
   int a[n];
   int numberOfOdds=fillAndFind(a,n);
   cout<<"Number of Odd values in the array is "<<numberOfOdds<<"\n";
   int a1[n];
   cout<<"Enter "<<n<<" integers for next array: \n";
   for(int i=0;i<n;i++)
   {
       cin>>a1[i];
   }
   cout<<"Enter a number you want to find in the array: ";
   int t;
   cin>>t;
   bool x=findTarget(a1,n,t);
   if(x==1)
       cout<<"True"<<endl;
   else
       cout<<"False"<<endl;
   double arr[n];
   cout<<"Enter "<<n<<" doubles for next array: \n";
   for(int i=0;i<n;i++)
   {
       cin>>arr[i];
   }
   double m=minValue(arr,n);
   cout<<"Minimum value is: "<<m<<endl;
   return 0;
}

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