Question

Write a C function named isSymmetric, the prototype of which is given below, that returns 1 if the elements of an array of integers named myArray of size n are symmetric around the middle. If the array elements are not symmetric, the function should return 0. Both the array and its size are specified as parameters.

Answer 1

#include <stdio.h>

int isSymmetric(int myArray[], int n);

int main() {
    int list1[] = {1, 4, 5, 4, 1};
    int list2[] = {4, 6, 8, 9, 7, 8, 6, 4};

    printf("%d\n", isSymmetric(list1, 5));
    printf("%d\n", isSymmetric(list2, 8));
    return 0;
}

int isSymmetric(int myArray[], int n) {
    int i;
    for (i = 0; i < n; ++i) {   // go through all indices of the array
        if (myArray[i] != myArray[n - i - 1]) { // if myArray is not symmetric at index i
            return 0;   // then return 0
        }
    }
    return 1;   // if all elements in the array are in symmetric order then return 1
}

Process finished with exit code o