Question

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Part A The circuit shown in (Figure 1) is used to make a magnetic balance to weigh objects. The mass in to be measured is hung from the center of the bar, which is in a uniform magnetic field of 1.90 T directed into the plane of the figure. The battery voltage can be adjusted to vary the current in the circuit. The horizontal bar is 64.0 cm long and is made of extremely lightweight material, so its mass can be neglected. It is connected to the battery by thin vertical wires that can support no appreciable tension; all the weight of the mass m is supported by the magnetic force on the bar. A R=4.95 2 resistor is in series with the bar, and the resistance of the rest of the circuit is negligibly small. Which point, a or b, should be the positive terminal of the battery? O Point a should be the positive terminal of the battery. O Point b should be the positive terminal of the battery. Submit Request Answer Part B Figure instrument can measure? 1 of 1 If the maximum terminal voltage of the battery is 175 V , what is the greatest mass m that Express your answer in kilograms to three significant figures. Battery IVO AE ? B Mmax = kg Х Х Bar Х X X X X X Х X X Submit Request Answer

Answer 1

fig. is in (6) Now Force , FB = mg and Solgthe force shows in battery. Il B = mg upwand. The current I in the bas must be to the right to produce it opwcase. To produce current in this direction, point a must be the positive terminal of the i. m = g IlB VIB Rg z 175 x 0.64 xl. 90 4.95 x 9.81 m = 4.38 kg -trg