Question

The batteries shown in the circuit in the figure (Figure 1) have negligibly small internal resistances Part A Find the current through the 30.0 22 resistor. Express your answer with the appropriate units. ? 130.00 Value Units Submit Request Answer Part B Find the current through the 20.082 resistor. Express your answer with the appropriate units. JA ? 120.00 - Value Units Figure < 1 of 1 Submit Request Answer Part C 30.0 12 Find the current through the 10.0 V battery. Express your answer with the appropriate units. 20.02 10.0 V 5.00 V μΑ ? 110.00 Value Units Submit Request Answer

Answer 1

In A B 나 At junction A I3 I 20.0n 30.0n -5.000 I t I = I3 10.05. I + I-I3=0 -0 D Ia Using kirchoff's voltase law in loop ABDA VA + 20.0 In- 5.00+ 30.0 Iz VA 7 20.0I + 30.0 Iz & 5.00 -

In loop ADEFA NA 30.0 Iz + 10.0 I 10.0 30.0 A 3I3 1 solving 1 we get - 0.583 A Iz - 0.25A 0.25A Iz 0.333 A A curreny through 30.on resistor I3 0.333 A ® currey through 20.0 resistor 172) 0.25A

through lo.orbattery Curreny I 0.583 A Note: Negative sigh in Ia, indicates, direction of I is opposite to that I have assumed