The batteries shown in the circuit in (Figure 1) have negligibly small internal resistances. Assume that E = 9.00 V and R = 21.9 Ω .
A) Find the current through the 30.0 Ω resistor.
B) Find the current through the 21.9 Ω resistor.
C) Find the current through the 9.00 V battery.
a)
Current through 30 ohm resistor = E/30
= 9/30 = 0.3 A <---- answer
b)
Current through R :
I = (9 - 5)/R = 4/21.9 = 0.183 A <---- answer
c)
Current through 9V :
= 0.3 + 0.183 = 0.483 A <------- answer
The batteries shown in the circuit in (Figure 1) have negligibly small internal resistances. Assume that...
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