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M Review Constants In the circuit shown in the figure (Figure 1), the 6.0 2 resistor is consuming energy at a rate of 27 J/s

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can see the Soln Here we turo resistors cet (200) then Rea = (2or) 11 (2or) 20x20 40 1or Redraw the ürmit I 172 → IA I 1 ²62Apply KUL in first loop -E + 17I, -6 I + 25 - 3 I t 13 I, = 0 -E + 3o I -9 I +25=0 -E + 30 (-1.9244) - 9 (2-1213) +25= 0 -E 5

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