Question

PHYS 212; Midterm 1 Review © 2020, The Pennsylvania State University 6. The figure shows a proton and an electron near a particle with mass 2 x 10-25 kg but unknown charge (labeled with a question mark). The electron is 1 um away from both the proton and the third particle. The three labeled points are evenly spaced with the particles. When the particle on the right is released from rest, it accelerates at 4.3 x 109 m/s to the right, what is the third particle's charge? ☺ . 0 . 0 . A. +6.0 x 10-19 C B. -1.2 x 10-12 C C. +8.0 x 10-19 C D. +1.2 x 10-19 C E. -8.0 x 10-19 C

Answer 1

In the question the Force between the two charges is calculated and acceleration is find out using ma=F simple formula and hence charge is find out.
Mass of padiele charge on Duisbon - Chaige on electosn = - 2x1525 kg + 1,6 X 10-19 € -116810790 thord partiele is released EV Tum um Forces on the third particle let the charge on third particle = x c As the charge o pt anel é is same and opposite Land pt is placed more far from ord particle Les compared to @ 10 0 0 - Acceleration of gid arlink is in right direction, I means force to more in rent direchon. It ly obvious' pi will produce repulsive force of to scarthed more maquitude .so, the charge of 3ta article

should be negative resultant foue е“ - 24pulus pota pt attractive force | son Helulauto fees would be in my li dirties Fin = kex Fpt 3 kpx D IY (10 672 T (2x1067 = 9x109x126x10-19 - | - Fpt = 4 x 10x 1,4 X 6", H = 14.4x10x 4x10-12 - 3.6x102x Mer force F¢-fpt - B S (14.443.6)21.07 x ___slida bina 10:18 x 10 x ace clecation produced in massa 2x10-25 kg xalxo'al = bx szolxo Qa 4,3 x 109miss o QX10-25 X 4.3 X 109 10.8 xlo? x x Win 8.6X10-16 = 10.8 x 10 ? x x w P o l 8,6% 10.16 7.96 X 10% 10,8 xlo? BX1079 C