Question

at 68°F is 99.992 ft between end marks when supported throughout under a 12-ib pull. What is the true horizontal length of a recorded distance AB for the conditions given in table below (Assume horizontal taping and all full tape lengths except the last.) Recorded Average Distance AB Temperature Means of Tension (ft) (°F) Support (lb) 86.06 68 Throughout 124.73 85 Throughout 86.35 50 Ends only 22 94.23 75 Ends only 25 12 15

please write clean!!!!

Answer 1

Please see solution in images below

96.8:- Ginen Data! Marked length of tape = 100 ft Type of matericed = sted. Cross-sectional area 'A' = 0.0025 in.2 weight = 2.3 16. Temprature of standardisation = 6808 ( 99.992) 12 16 Standardised pull - Calculations : Recorded distance AB 86.06ft. = 68°F Average temprature - Since Means of support = throyout Tension 12 lb. auerage pe temprature is some as standardüed tempralue auerage pull is also same is supported throughout it's length, Hence no correction shall be applied. The Horisontal length = 86.06 ft and

tol, Calculated Al temp. X 185-68) for AB 124.73.11) Average tempralure = 95°F (more than standardised temprature Hence, Temprature correction is applicable) Means ; Temprature Comection ; frue = temp. Correan of temprature exot = 124.73 X7.213x10 -6 OF b= length Ab = 124.73 H 2 = Coefficient of thermal expansion of skel 7.213 x 106 lr At = change in temprotein = 65-68 = 17°F 0.0153 Tension applied - 15 16. (more than standard puy Pull Correction = (P-Po) L Hence pull correction shall AE P = Applied tension L= length of tape / distace. A = Gross-sech Area 229 X 10 lblina Po= standard pull tension E = modules of elasticity of mores 41= temp. be applied)

Pel Corection = (15-12) 124.73 0.00254 29x106 5.1617103 f. Correded length= Tempraluse Correction + ball Coverchia 124.73 + 0.0153 + 0.00516 124.75th AB: 86.354 Avg. Tempratice = 500F Supported on Ends only ( Hence sog correction will also be applied in additim to tempratur Correction and pull connection) Tension : 22/b. 0 Tempralie Conection, 아 = 86-35 x 7.213 x 10 (50-68) -6 = 0.011 ft C negative sign showes veduction in length)

(li) Puy Correction : (P-Po)L AE - (22-12) x 86.35 0.0025% 29x10-6 = 0.012 ft. ciii) 8²L3 Correction : WE 24P2 24p2 where ; Y = weight of tape per unit length total man or weight of tape Le unsupported length of tape (distance) PoE opplied pull during meesweet (NOTE!- sug correction is always negative ( 2.3²x 86.35 0.039ft. 24 x 22° W= Total corrected length 86.35 + temprature Correction + Pull Correction + Sag correction 8635 -0.011 +0.012 — 0.039 86.312 ft

AB: 94.23th Average temprotes = 75°F on Ends 25lb supported only Tension (1) Temprature Connection to exos 94.23 x 7.213X100 x(75-68) 0.0047 H. Lil Pull Correction = (P-fo) AE =25-12) * 94.23 0.01741. 0.00250 29x106 clip Sof Correction - we aux 252 -0.033H Total corrected length 94.23 +0.0047 +0.017-0.033 = 94.218H. Means of Supt Tensim (n) Comected length H 86.06 68 Throughout 86.06 65 IS Throughout 124.75 86.35 Jo 22 86.312 94.23 25 94.218 &.32 X 94.27 24P2 A B (4) Aug. Temp 12 124.73 Ends only 75 Ends only