A system has a net charge of −5.328×10−17 C . It consists of electrons and protons, in a total number of 1505 particles.
Let the no.of protons = a
no.of electrons=b
Total no.of particles, a+b= 1505 .............(1)
Net charge, Q=−5.328×10^−17 C
But net charge id due to protons and electrons
Q= ae-be
where e is charge on electron or proton
Therefore, Q=(a-b)e=(a-b)*1.6*10^-19
but Q=−5.328×10^−17 C =(a-b)*1.6*10^-19
a-b=3.33*10^2
a-b=-333 .............(2)
solving (1) and (2) we get
The no.of protons, a= 586
b=919The no.of electrons, b=919
Answer (b)
Mass of the system, M=a*m1+b*m2
where m1 is mass of proton = 1.9*10^-27 kg
m2 is mass of electron=9.3^-31 kg
M=586*1.9*10^-27 kg + 919*9.3^-31 kg
M=1113.4*10^-27+0.85*10^-27
M=1114.25*10^-27 kg
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