Question

#9 is used to slove #10

Write an equation for the line described. Give your answer in standard form. 9) Passes through the points (-4,7) and (-2,-9) -9-(0) -2-4-4 = -11 14) = -16 - 8 9.7=-80(x+4 =-74-8x - 32 = 8xty-72-32 Use the previous problem to answer this question. Write your answer in either form. 10) Write an equation for a line parallel to the line from #9 8x+y=-25 1

Answer 1

9) Given points led (X,Y)=(-4,7) (X2,4)=(-2,-4) The equation of line passing through points (x,,9.) S (x2, 9₂) is 9-4, = 4,-4, 22-X (x-x,) y=+= -9-7 (2-64)) -2-6h) y-7= -16 -244 beth) y-7 - (x+4) y-73-3(x+he) Y-7--8X-32 8x+y +25=0

10) The car of line parallel to 8x+4+25=0 is The slope is ma -3 The ea of line is y=mxte y=-3X + 4+ 8x =( 8x+y-(- EC#-25) Hore CER-{_25} at caras lines become coincident lines. so The two the eqr of line parallet to 8x+y+2520 is zx ty-(-0 (except C=~25