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Assume that hybridization experiments are conducted with peas having the property that for offspring there is a 0.25 probabil

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Answer #1

(a)

mean = \mu = np = 32 X 0.25 = 8

standard deviation = 0 = npq = 32 x 0.25 X 0.75 = 2.45

(b)

Hi - 20 = 8 - (2 x 2.4495) = 8 – 4.8990 = 3.1

Values of 3.1 peas or fewer are significantly low.

u + 20 = 8+ (2 x 2.4495) = 8 + 4.8990 = 12.9

Values of 12.9 peas or greater are significantly high.

(c)

The result is significantly low because 1 peas with green pods is less than 3.1 peas.

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