Question

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Answer 1

Given data:- Dimension of the plate a*b = 380mm*196mm

Linear deflection of both the edges

СE1mm

strain shear shear Ve -Vę

Refer diagram

Expression for angle $\alpha$

tana a

1.7 tana 380 29

0,2563

a 0.2563°* 180°

4.4736510rad

Expression for angle $\beta$

tanB

1.7 tan 19E

$\beta = 0.4969^{\circ}$

B0.4969° 180

B8.6732 103rad

Total shear strain can be given as

$\gamma =\alpha +\beta$

but $\beta$ is negative according to our sign convention.

$\gamma = 4.4735*10^{-3}-8.6732*10^{-3}$

$\gamma = -4.1996*10^{-3}rad$

-4199.67urad