A 25-kg chandelier hangs from a ceiling on a vertical 4.0-m-long wire.
Part A.
What horizontal force would be necessary to displace its position 0.12 m to one side?
Part B
What will be the tension in the wire?
A)
at 12 m :
Angle from vertical, x= asin (0.12/4) = 1.72 degree
At this point:
T cos x = m*g
T*cos 1.72 = 25*9.8
T= 245.11 N
Forceapplied must baalnce T* sin x
T sin x = F
F = 245.11 * sin 1.72
F=7.36 N
B)
As calculated above,Tenstion, T= 245.11 N
A 25-kg chandelier hangs from a ceiling on a vertical 4.0-m-long wire. Part A. What horizontal...
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