You need a capacitance of 70 μF , but you don't happen to have a 70 μF capacitor. You do have a45 μF capacitor. What additional capacitor do you need to produce a total capacitance of 70 μF ?
You need a capacitance of 70 μF , but you don't happen to have a 70...
You need a capacitance of 55.0 ?F, but you don't happen to have a 55.0 ?F capacitor. You do have a 85.0 ?F capacitor. Part A What additional capacitor do you need to produce a total capacitance of 55.0 ?F? Express your answer with the appropriate units. Part B Should you join the two capacitors in parallel or in series?
You need a capacitance of 55.0 uF, but you don't happen to have a 55.0 uF capacitor. You do have a 90.0 uF capacitor. Part A What additional capacitor do you need to produce a total capacitance of 55.0 uF? Express your answer with the appropriate units. ► View Available Hint(s) μΑ ? C = 207 uF. Submit Previous Answers
Two capacitors connected in parallel produce an equivalent capacitance of 40.0 μF but when connected in series the equivalent capacitance is only 7.1 μF . What is the individual capacitance of each capacitor?
1) You calculated a equivalent capacitance of 0.42 μF ± 0.08 μF. If the manufacturer has labeled the capacitor as 0.5 μF ± 10%, is this consistent with your result? yes, no, or cannot be determined? 2) You calculated a value of 0.53 s ± 0.06 s for the time constant from your graph. If you used a 1MΩ resistor with a tolerance of 10%, what is the equivalent capacitance of your circuit (including the uncertainty)?
Two capacitors are connected in series to a 50-V battery. The capacitance C1 = 5 μF and the capacitance C2 = 15 μF. a. What is the charge on capacitor C1? (The answer is 187.5 μC I just don't know how to arrive at that answer)
The C1 -2.0 uF and 3.0 uF capacitor equivalent capacitance is X1-5.0 μF. Likewise, the C2-3.0 μF and 6.0 μF capacitors are also in parallel and have an equivalent capacitance of Y1-9.0屹The upper branch in Figure 26.11b now consists of a 4.0 μF capacitor and a 5.0 μF In series, which combine to give x2 according to the following equation. rs are in parallel and combine according to Ceq C1+C2. Their Likewise, the lower branch in Figure 26.11b consists of...
Two capacitors connected in parallel produce an equivalent capacitance of 45.0 μF but when connected in series the equivalent capacitance is only 4.4 μF . What is the individual capacitance of each capacitor? Enter your answers in ascending order. Express your answers using two significant figures separated by a comma.
10) You have four capacitors. (a) You need a capacitor of larger capacitance than all of them. How do you connect these capacitors to get larger capacitance? -5 pt (b) How do you connect them to get smaller capacitance? Is the resultant capacitance smaller than all or average of all?- 5 pt
SHOW YOUR WORK TO GET FULL CREDIT. capacitors of capacitance 6.00μF and 8.00 μF are connected in parallel. The combination is figure. (6 POINTS) 15) Two then connected in series with a 120-V voltage source and a 14.0-uF capacitor, as shown in the 6.00 μF 14.0 μF 8.00 μF (a) what is the equivalent capacitance of this combination? (b) What is the charge on the 6.00-F capacitor? (e) What is the potential difference across the 6.00-4F capacitor?
25. a) What capacitance do you need to produce a resonant frequency of 1.00 GHz, when using an 8.00 nH inductor? b). What inductance do you need to produce a resonant frequency of 60.0 Hz, when using a 2.00 uF capacitor