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You need a capacitance of 55.0 uF, but you dont happen to have a 55.0 uF capacitor. You do have a 90.0 uF capacitor. Part A

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Answer #1

Let the given capacitor be C_1 = 90 \ \mu F

Required total capacitance is C_t = 55 \ \mu F

Let C be the additional capacitor

Let the capacitors C_1 and C be connected in series and their resultant be C_t

Therefore,

\\C_t = \frac{C * C_1}{C + C_1} \\\\55 = \frac{C * 90}{C + 90} \\\\55 * (C + 90) = 90C \\\\55C + 4950 = 90C \\\\35C = 4950 \\\\C = \frac{4950}{35} \\\\C = 141.43 \ \mu F

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