Question

is defined as - N for N40 and 0 for N -0. Find 3. Thers complement of an n-digit number N in base 2. the nines complement
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Answer #1

1 Ans)

N=13812

n=5 (which is number of digits in the number)

r=9 (here find 9's complement

so

by substitute in the formula as r^n-N

such that=>

9^5-13812

59049-13812

=45237

2 ans)

N=32120

n=5

r=5

so

5^5-32120

=-28995

#but the actual r's compliment without formula is good other wise above we need some modification

9's complement

99999

-13812

than

86817

five complement is possible high one is

55555

32120

then

23245

#if you have any doubt or more information needed comment below..i will repond as possible as soon..thanks,..

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