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1. Gausss Law and Electrostatic Potential 10cm 5cm Figure 1. Figure 1 shows a spherical volume of radius 10cm with uniformly distributed charge. The volume charge density isp -100nCm. The permittivity of the sphere is the same as free space. Permittivity of Free Space: ausss Law: Eo8.854 x 10-12 F/m , D . ds-otot ctric Flux Density:
(a) Find the total charge in the entire 10cm sphere and the charge in the embedded smaller sphere with a radius of Scm as shown in figure (two sets of charge). (5) (b) Using Gausss law, find the electric field strength at a radial distance of 5cm (on the inner sphere). (5) (c) At what radial distance outside the 10cm sphere would the electric field strength be equal to the field strength at a radial distance of 5cm (from part (b)). (5)
es of 10cm and 20cm. Note the equal to the (d) What is the electrostatic potential at radial distanc potential due to the distributed charge in the region ou potential due to the equivalent point charge locat tside the sphere is ed at the center of the sphere. (5) (e) if the work done when an unknown point charge is moved from a radial distance of 10cm to 20cm is +5nJ, find the magnitude and polarity of the unknown point charge. (7) (f) Find the radial distance from the center of the charged sphere of a point where the total electric field is zero when the point charge in part (e) is at a radial distance of 20cm. Note the electric field due to the distributed charge in the sphere is cancelled by the electric field due to the point charge at a point on the line joining the point charge to the center of the sphere at a radial distance greater than 20cm. (8)
(8) Find the radial distance from the center of the charged sphere of a point where the net electrostatic potential is zero when the point charge in part (e) is at a radial distance of 20cm. Note the net potential will be due to both the distributed charge in the sphere and the point charge and this will be zero at a radial distance in the range 10cm s R s 20cm. (h) By changing the charge density of the distributed charge in the sphere, the total electric field due to the new distributed charge and the point charge from part (e) is forced to be zero at a point on the line joining the point charge to the center of the sphere at a radial distance of 10cm from the center of the sphere. Find the magnitude and polarity of the new volume charge density in the sphere. (8)
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